Count the prime number in a certain range in Java
In Java, counting prime numbers within a specific range can be accomplished using various techniques. One common approach is to iterate through the numbers in the range and check if each number is prime. By implementing this iterative method, you can efficiently determine the total count of prime numbers within the given range.
Count the prime number in a certain range
public class PrimeNumberCounter { public static void main(String[] args) { int lowerBound = 1; int upperBound = 100; int count = 0; for (int number = lowerBound; number <= upperBound; number++) { if (isPrime(number)) { count++; } } System.out.println("The number of prime numbers in the range [" + lowerBound + ", " + upperBound + "] is: " + count); } public static boolean isPrime(int number) { if (number <= 1) { return false; } for (int i = 2; i <= Math.sqrt(number); i++) { if (number % i == 0) { return false; } } return true; } }
OUTPUT:
The number of prime numbers in the range [1, 100] is: 25
To count the prime numbers within a certain range in Java, you can follow these steps:
- Prompt the user to enter the lower and upper bounds of the range.
- Initialize a counter variable to keep track of the number of prime numbers.
- Iterate through each number within the range.
- For each number, check if it is prime by dividing it by all numbers from 2 to its square root. If any divisor is found, the number is not prime.
- If the number is prime, increment the counter.
- After iterating through all the numbers in the range, the counter will hold the total count of prime numbers.
- Display the count of prime numbers to the user.