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Check if a number is an Armstrong Number or not in PYTHON

By Kalki Pareshkumar Bhavsar

A Python implementation to check whether the input number is an Armstrong number (a number that is equal to the sum of its digits each raised to the power of the number of digits) or not.

Armstrong Number

Hey CodeSpeeder!

Numbers are amazing when it comes to finding patterns within the number themselves. 

Consider a number, for example, 153. There are a total of 3 digits in the number: 1, 5, and 3 whose 3rd power is 1, 125, and 9 respectively. Add them up and you'll get 153, the input number again. Isn't this fascinating! Such numbers are specially named as Armstrong Number.

Let's mathematically formulate this! Consider a number num with n digits be expressed as dndn-1...d1. num is an Armstrong number if the following condition is satisfied:

dndn-1...d1 = (dn)n + (dn-1)n +...+ (d1)n 

For example:

Number 153 is a 3-digit number. Hence, n=3. From the above condition, LHS=153 while RHS = 13 + 53 + 33 = 153 = LHS. 153 is an Armstrong number.

Number 135 is also a 3-digit number. Here, LHS=135 while RHS = 13 + 33 + 53 = 153 = RHS. Hence, 135 is not an Armstrong number.

Program

The following is the Python implementation for checking whether the input number is an Armstrong number or not:

# function to check if the number n
# is Armstrong number or not
def isArmstrongNumber(num):
    sumVal = 0  # Sum value
    n = len(str(num))  # total digits in the number num
    # calculate the sum of the nth power of each digit in number num
    for digit in str(num):
        sumVal += int(digit) ** n

    # if the sumVal is equal to input number num,
    # num is an Armstrong number
    if sumVal == num:
        return True
    else:
        return False

 

The below is the driver code to check the function isArmstrongNumber() on various test-cases:

# Test-case 1: 153 is an Armstrong Number
print("Is 153 an Armstrong Number? - ", isArmstrongNumber(153))
# Test-case 2: 135 is not an Armstrong Number
print("Is 135 an Armstrong Number? - ", isArmstrongNumber(135))
# Test-case 3: 407 is an Armstrong Number
print("Is 407 an Armstrong Number? - ", isArmstrongNumber(407))
# Test-case 4: 1634 is an Armstrong Number
print("Is 1634 an Armstrong Number? - ", isArmstrongNumber(1634))
# Test-case 5: 115132219018763992565095597973971522401 is an Armstrong Number
print("Is 115,132,219,018,763,992,565,095,597,973,971,522,401 an Armstrong Number? - ", isArmstrongNumber(115132219018763992565095597973971522401))

The output of the following code is:

Is 153 an Armstrong Number? -  True
Is 135 an Armstrong Number? -  False
Is 407 an Armstrong Number? -  True
Is 1634 an Armstrong Number? -  True
Is 115,132,219,018,763,992,565,095,597,973,971,522,401 an Armstrong Number? -  True

Fact Point! Thinking Emoji [Download Thinking Emoji in PNG] | Emoji Island

There are only 89 Armstrong numbers of which the largest is 115,132,219,018,763,992,565,095,597,973,971,522,401

with 39 digits. (reference)

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Submitted by Kalki Pareshkumar Bhavsar (KalkiBhavsar)

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