Convert Decimal Number to a Number with base N in C++

By Jay Parmar

A simple C++ program that lets you convert a decimal number (base 10) to a base N number using an array of characters

The code consist of a C++ approach of converting a decimal number into a number with base given by the user.

 

Code asks the user to enter a number in base-ten (10) and a base in which the code has to calculate the value of!

 

We can convert our number to Binary, Octal or in any base upto Hexadecimal.

 

If the user inputs a base less than Binary (2) or more than Hexadecimal (16), the process terminates the program and exits the code.

 

Here's a snapshot of how the program appears: