Pattern Printing using Loops in C++

pattern_magic/

In this project, I will show you how to print following pattern using for loops in C++ programming language.

Problem Statement: You have to print a pattern of numbers from 1 to n as shown below. Where n is an input. Each of the numbers is separated by a single space.Input:

The input will contain a single integer n. Constraints:

1<=n<=1000 Output:

Print the demanded pattern.

Example

Input:

Output:

4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4

Following is the source code in C++ programming language for above problem statement:

#include<bits/stdc++.h>
typedef long long ll;
using namespace std;
int main(){
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int n;
    cin>>n;
    int t=2*n;
    for(int i=1;i<=n;i++){
        int k=n;
        for(int j=1;j<=t-1;j++){
            if(j<i){
                cout<<k--<<" ";
            }else if(j>=i && j<=t-i){
                cout<<k<<" ";
            }else{
                cout<<++k<<" ";
            }
        }
        cout<<"\n";
    }
    for(int i=n-1;i>=1;i--){
        int k=n;
        for(int j=1;j<=t-1;j++){
            if(j<i){
                cout<<k--<<" ";
            }else if(j>=i && j<=t-i){
                cout<<k<<" ";
            }else{
                cout<<++k<<" ";
            }
        }
        cout<<"\n";
    }
}

Coders Packet

Pattern Printing using Loops in C++

Example

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